Man, I'd love to see this in a game, somehow. I remember at some math program I was at, the teacher in charge posed this puzzle:

--spinner A always comes up 4.
--spinner B comes up 1, 5, or 6 with equal chances for each.
--spinner C comes up 2, 3 or 7, with equal chances for each.

The teacher lets you pick first. Which is the best one to pick?

B is. It loses to C 55% of the time--1/5/6 vs 7 and 1 vs 2/3. C loses to A 2/3-4, and A to B 4-5/6, 66% of the time.

Offshoot question:

Design 3 wheels A, B and C so that each is equally bad for the first person to play.

I spent some time late at work scratching this problem out. I don't know why I didn't do it earlier. But that I like puzzles like these tells me about my taste in games and why it might not match up with people's here. Still, I hope it's fun to tinker with.

Offshoot answer:

Wheel 1=4
Wheel 2 = g chance of 5, 1-g chance of 2
Wheel 3 = g chance of 3, 1-g chance of 6
Where g = the golden ratio, e.g. (sqroot(5)-1)/2.

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	zippdementia - May 19, 2010 (09:56 AM) i don't understand the puzzle. what am I choosing these wheels based on?
	aschultz - May 24, 2010 (02:53 PM) Whichever gets the bigger number.